16x^2+8x-63=0

Solution for 16x^2+8x-63=0 equation:

16x^2+8x-63=0

a = 16; b = 8; c = -63;
Δ = b2-4ac
Δ = 82-4·16·(-63)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-64}{2*16}=\frac{-72}{32}
=-2+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+64}{2*16}=\frac{56}{32}
=1+3/4
$